Posted 24 February 2007 - 02:27 PM
It might be easier to look at cost of turns from the point of view of the WHOLE the turn rather than increments of the turn.Example 1:My ship, the USS Bumfuzzle, is doing 40kts. I decide in the next turn to make a 90 degree (which is 5 ticks around the turn gauge) turn. I first proceed straight for 500yd (the advance into the turn) using 5kts.I then proceed the 5 ticks around the turn gauge to my final point. Since this is a turn OVER 30 degrees, the cost will be 10kts (2kts for each tick on the turn gauge) for the turn.I then proceed on my way using my remaining 25kts.Example 2:Now this time I want the Bumfuzzle to make a small change of course of 18 degrees (only 1 tick around the gauge).I still proceed straight for 500yds (it still takes that long for the rudder to respond) using 5kts.I then proceed 1 tick around the turn gauge to my final point. Since this is a turn UNDER 30 degrees, the cost will only be 1kt (1kt for the single tick on the turn gauge) for the turn.I then proceed on my merry way using my remaining 34kts.Example 3:Now, I want the USS Bumfuzzle to make a 2 tick (36 degree) turn (still doing 40kts). I first proceed straight for 500yd, using 5kts.I then proceed the 2 ticks around the turn gauge to my final point. Since this is a turn OVER 30 degrees, the cost will be 4kts (2kts for each tick on the turn gauge) for the turn.Once again, I then proceed on my way using my remaining 31kts.The key thing to remeber is the cost per tick depends on the size of ENTIRE turn. If the turn is OVER 30 degrees, then each tick will cost 2kts. If UNDER 30 degrees, the cost is 1kt per tick.I hope this clarifies things...